Christina Aguilerahad jaws dropping to the floor as she took to the stage to perform at a fundraiser held for Hillary Clinton on Monday night, and it wasn't just because of her incredible vocals. The 35-year-old debuted a drastic makeover, as she revealed she had dyed her blonde tresses a fiery shade of red.
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Christina Aguilera debuted her new red hairstyle
Before heading out to the performance, Christina delighted her 2.6 million Instagram followers with a sneak peek of her striking new hairdo as she got ready backstage. Showing off her beauty credentials, the star complemented the striking new hair colour with a statement shade of red lipstick, completing her make-up with bold winged eyeliner.
Her outfit was equally as eye-catching, with the singer opting for a black tailored jacket and studded leggings for her performance at the fundraiser, which saw a star-studded guestlist including Eva Longoria, John Legend and his wife Chrissy Teigen, and Stevie Wonder.
The singer performed at the fundraiser held in Los Angeles
While Christina's blonde tresses have become one of her trademark looks, in recent weeks it seems the star has been experimenting with her hair. Never one to shy away from an edgy style, earlier this year Christina revealed on Instagram that she had dyed her locks a showstopping shade of lavender.
The singer debuted the new hairstyle as she filmed an episode of The Voice USA, for which she is a judge.
Christina dyed her hair purple earlier this year
Wearing her hair down in a poker straight style, the Genie in a Bottle hitmaker added a touch of edge by braiding the front section of her hair and adding a series of hoops throughout the plait. Celebrity hairstylist Chris Appleton, who created the style, gave his own Instagram a closer look at Christina's locks, with a close-up snap of the hooped braid.
Christina is no stranger to dyeing her hair into colourful hues. Previous years have seen her experiment with everything from purple and pink dip dyes to platinum blonde, and even a striking shade of black.